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NEW QUESTION: 1
Syslog管理者がAmazon EC2サーバーのトラブルシューティングを行い、接続されたAmazon EBSブロックストレージボリュームへのデータの読み書きのボトルネックを発見しました。インスタンスは大きく、EBSは最初にプロビジョニングされた1,000 IOPSでio1です。管理者はプロビジョニングされたIOPSを2,000に増やしますが、パフォーマンスは向上しません。
管理者は次に何をすべきですか？
A. 音量をgp2に変更して大きくします。
B. インスタンスタイプをt2ラージに変更してください。
C. ボリュームをAmazon S3に変更し、ランダムキーの先頭に追加します
D. インスタンスタイプをc4 xlargeに変更します。
Answer: C
NEW QUESTION: 2
A. Option B
B. Option C
C. Option A
D. Option D
Answer: C
NEW QUESTION: 3
Which one of the following queries selects the customer whose order has the highest total price?
A. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createquery(customer.class)
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
B. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.cteateQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
C. CriteriaBuilder cb = ...
CriteriaQuery<Customer> cq = cb.createQuery(Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer_.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = sq.from(Order.class);
sq.select (cb.max ( subo.get (Order_ . Total Price) ) ) ;
cq.where(sq.all(o.get(Order_.totalPrice)));
D. CriteriaBuilder cb = ...
Criteria Query <Customer> cq = cb.create Query (Customer.class);
Root<Customer> c = cq.from(Customer.class);
Join<Customer, Order> o = c.join(Customer__.orders);
cq.select(c).distinct(true);
Subquery<Double> sq = cq.subquery(Double.class);
Root<Order> subo = cq.correlate(o);
sq.select(cb.max(subo.get(Order_.totalPrice)));
cq.where(cb.equal(o.get(Order_.totalPrice), cb.all(sq)));
Answer: C
Explanation:
Explanation/Reference:
Incorrect: Not a, not b, not C: use .from not .correlate.
Example:
CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery<Number> cq = qb.createQuery(Number.class);
Root<Event> root = cq.from(Event.class);
cq.select(qb.max(root.get("dateProcessed")));
cq.where(qb.equal(Event.get("org"), qb.parameter(MyOrgType.class, "myOrg"))); em.createQuery(cq).setParameter("myOrg", myOrg).getSingleResult();
Note:
max(Expression<N> x)
Create an aggregate expression applying the numerical max operation.
Reference: javax.persistence.criteria, Interface CriteriaBuilder
NEW QUESTION: 4
Which are valid entry points for connecting to WebDAV in an IBM WebSphere Portal environment?
A. fs-typlist, themelist, skinlist
B. themes, skins, fs-type1
C. themes, skins, fs-types
D. themelist, skinlist, fs-type1
Answer: D
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