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NEW QUESTION: 1
2 TBのデータファイルを保存するオンプレミスのファイルサーバーがあります。
データファイルを中央ヨーロッパ地域のAzure Blobストレージに移動する予定です。
データアカウントとストレージアカウントのレプリケーションソリューションを格納するには、ストレージアカウントの種類を推奨する必要があります。ソリューションは次の要件を満たす必要があります。
*単一のAzureデータセンターに障害が発生した場合に利用できます。
*ストレージ階層をサポートします。
*コストを最小限に抑えます。
何を勧めますか？回答するには、回答領域で適切なオプションを選択します。
注：それぞれの正しい選択は1ポイントの価値があります。
Answer:
Explanation:
Explanation
Box 1: Blob storage
Blob storage supports storage tiers
Note: Azure offers three storage tiers to store data in blob storage: Hot Access tier, Cool Access tier, and Archive tier. These tiers target data at different stages of its lifecycle and offer cost-effective storage options for different use cases.
Box 2: Zone-redundant storage (ZRS)
Data in an Azure Storage account is always replicated three times in the primary region. Azure Storage offers two options for how your data is replicated in the primary region:
* Zone-redundant storage (ZRS) copies your data synchronously across three Azure availability zones in the primary region.
* Locally redundant storage (LRS) copies your data synchronously three times within a single physical location in the primary region. LRS is the least expensive replication option, but is not recommended for applications requiring high availability.
References:
https://cloud.netapp.com/blog/storage-tiers-in-azure-blob-storage-find-the-best-for-your-data
https://docs.microsoft.com/en-us/azure/storage/common/storage-redundancy
NEW QUESTION: 2
You are designing cloud protection for a customer who is using Dell EMC Cloud Snapshot Manager.
Which Microsoft Azure resource is supported with Snapshot Management?
A. Elastic Compute Cloud
B. Relational Database Service
C. Managed Virtual Machine
D. Elastic Block Store
Answer: C
NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class complex{
double re;
double im;
public:
complex() : re(0),im(0) {}
complex(double x) { re=x,im=x;};
complex(double x,double y) { re=x,im=y;}
void print() { cout << re << " " << im;}
};
int main(){
complex c1;
double i=2;
c1 = i; c1.print(); return 0; }
A. It prints: 1 1
B. It prints: 2 0
C. It prints: 2 2
D. It prints: 0 0
Answer: C
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