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NEW QUESTION: 1

A. Option B
B. Option A
C. Option C
D. Option D
Answer: B,C

NEW QUESTION: 2
Which of the following statements are CORRECT about configuring the clock for a PRA trunk on U1900? (Multiple Choice)
A. The clock is configured to prevent frame slip caused by asynchronous clocks.
B. The clock source can be the U1900 itself or the peer device.
C. If the U1900 provides the clock source, you still need to configure the clock source.
D. If the U1900 is connected to multiple devices using Tl/El trunks, each trunk requires a clock source.
Answer: A,B

NEW QUESTION: 3
What is the purpose of REVOKEREMOTEACCESS?
A. Disable the web client
B. Restrict access from any node
C. Restrict administrators with client access privilege
D. Disable remote access to the server
Answer: C
Explanation:
Explanation/Reference:
Reference https://www.ibm.com/support/knowledgecenter/en/SSEQVQ_8.1.0/client/ r_opt_revokeremoteaccess.html

NEW QUESTION: 4
If an Ethernet port on a router was assigned an IP address of 172.16.112.1/20, what is the maximum number of hosts allowed on this subnet?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: A
Explanation:
Explanation
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256.
Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255.
The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2


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20 minus one if you have subnet zero enabled, or minus 2 if not.
You asked about the number of hosts. That will be 32 minus the number of network bits, minus two. So calculate it as (2