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NEW QUESTION: 1
開発者が、ユーザーにログインを要求しないモバイルアプリケーションを作成しています。
ユーザーにAWSリソースへのアクセスを許可するための最も効率的な方法は何ですか？
A. IDプロバイダーを使用してアプリケーションと安全に認証します。
B. ユーザーがアプリケーションにアクセスしたときにIAMユーザーを作成するためのAWS Lambda関数を作成します。
C. Amazon Cognitoを使用して、認証されていないユーザーを、リソースへのアクセスが制限されているIAMロールに関連付けます。
D. AWS KMSを使用して認証情報を作成し、アプリケーションを使用するときにこれらの認証情報をユーザーに適用します。
Answer: D

NEW QUESTION: 2
Examine the SQL statement that creates ORDERS table:
CREATE TABLE orders (SER_NO NUMBER UNIQUE, ORDER_ID NUMBER, ORDER_DATE DATE NOT NULL, STATUS VARCHAR2(10) CHECK (status IN ('CREDIT', 'CASH')), PROD_ID NUMBER REFERENCES PRODUCTS(PRODUCT_ID), ORD_TOTAL NUMBER, PRIMARY KEY (order_id, order_date));
For which columns would an index be automatically created when you execute the above SQL statement?
(Choose two.)
A. STATUS
B. SER_NO
C. composite index on ORDER_ID and ORDER_DATE
D. ORD_TOTAL
E. PROD_ID
F. ORDER_ID
Answer: B,C
Explanation:
Explanation/Reference:
Explanation:
Index exist for UNIQUE and PRIMARY KEY constraints
Incorrect answer:
BORDER_ID is neither UNIQUE nor PRIMARY KEY
CSTATUS is neither UNIQUE nor PRIMARY KEY
DPROD_ID is neither UNIQUE nor PRIMARY KEY
EORD_TOTAL is neither UNIQUE nor PRIMARY KEY
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 10-15

NEW QUESTION: 3
Refer to the exhibit.

Which command would verify if PBR reacts to packets sourced from 172.16.0.0/16?
A. show ip route
B. show access-lists
C. show policy-map
D. show route-map
Answer: D
Explanation:
The "show route-map "route-map name" displays the policy routing match counts so we can learn if PBR reacts to packets sourced from 172.16.0.0/16 or not.

NEW QUESTION: 4
View the Exhibit and examine the structure of the PRODUCTS table.

You want to display the category with the maximum number of items.
You issue the following query:
SQL>SELECT COUNT(*), prod_category_id
FROM products
GROUP BY prod_category_id
HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM products);
What is the outcome?
A. It executes successfully and gives the correct output.
B. It generates an error because the subquery does not have a GROUP BY clause.
C. It executes successfully but does not give the correct output.
D. It generates an error because = is not valid and should be replaced by the IN operator.
Answer: B