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NEW QUESTION: 1
A Developer is working on an application that tracks hundreds of millions of product reviews in an Amazon DynamoDB table. The records include the data elements shown in the table:
Which field, when used as the partition key, would result in the MOST consistent performance using DynamoDB?
A. productID
B. comment
C. starRating
D. reviewID
Answer: A
Explanation:
Explanation
Refer AWS documentation - DynamoDB Design partition key
The partition key portion of a table s primary key determines the logical partitions in which a table's data is stored. This in turn affects the underlying physical partitions. Provisioned I/O capacity for the table is divided evenly among these physical partitions. Therefore a partition key design that doesn't distribute I/O requests evenly can create "hot" partitions that result in throttling and use your provisioned I/O capacity inefficiently.
The optimal usage of a table's provisioned throughput depends not only on the workload patterns of individual items, but also on the partition-key design. This doesn't mean that you must access all partition key values to achieve an efficient throughput level, or even that the percentage of accessed partition key values must be high. It does mean that the more distinct partition key values that your workload accesses, the more those requests will be spread across the partitioned space. In general, you will use your provisioned throughput more efficiently as the ratio of partition key values accessed to the total number of partition key values increases.
NEW QUESTION: 2
Which tool is available on an OSSV client to assist in starting or stopping the OSSV service, modifying NDMP settings, enabling debugging, and capturing trace files?
A. Operations Manager
B. Svconfigurator GUI
C. Protection Manager
D. svdebug.exe
Answer: B
Explanation:
http://synergy-ds.com/netapp/tr-3466.pdf
NEW QUESTION: 3
ICMPエコーベースのIP SLAの2つの特性はどれですか？ （2つ選択）
A. 設定可能なベースでレポートするためのトラフィック統計を集約します
B. 収集されたデータを記録および維持するには、リモートデバイスが必要です
C. ネットワークパフォーマンスを監視するために継続的なトラフィックを生成します
D. RSPANを使用して、ネットワーク統計を指定されたリモートポートに報告できます。
E. トラフィックを測定して、Ciscoルーターから指定されたエンドデバイスへの接続の信頼性を判断します。
Answer: B,E
NEW QUESTION: 4
The EMPLOYEES table contains these columns:
EMPLOYEE_ID NUMBER(4)
ENAME VARCHAR2 (25)
JOB_ID VARCHAR2(10)
Which SQL statement will return the ENAME, length of the ENAME, and the numeric position of the letter "a" in the ENAME column, for those employees whose ENAME ends with a the letter "n"?
A. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, ,-1,1) FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
B. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, -1, 1) = 'n';
C. SELECT ENAME, LENGTH(ENAME), INSTR(ENAME, 'a') FROM EMPLOYEES WHERE SUBSTR(ENAME, -1, 1) = 'n';
D. SELECT ENAME, LENGTH(ENAME), SUBSTR(ENAME, -1,1) FROM EMPLOYEES WHERE INSTR(ENAME, 1, 1) = 'n';
Answer: C
Explanation:
INSTR is a character function return the numeric position of a named string.
INSTR(NAMED,'a')
Incorrect answer:
B Did not return a numeric position for 'a'.
C Did not return a numeric position for 'a'.
D Did not return a numeric position for 'a'.
Refer: Introduction to Oracle9i: SQL, Oracle University Study Guide, 3-8
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