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NEW QUESTION: 1
Your network contains an Active Directory domain named contoso.com. The network contains two servers named Server1 and Server2.
You deploy Active Directory Certificate Services (AD CS). The certification authority (CA) is configured as shown in the exhibit. (Click the Exhibit button).

You need to ensure that you can issue certificates based on certificate templates.
What should you do?
A. On Server1, install the Network Device Enrollment service role service.
B. Configure Server2 as an enterprise subordinate CA.
C. Configure Server2 as a standalone subordinate CA.
D. On Server1, run the Add-CATemplate cmdlet.
Answer: B

NEW QUESTION: 2
You have a Windows Server 2008 R2 Enterprise Root CA.
Security policy prevents port 443 and port 80 from being opened on domain controllers and on the issuing CA.
You need to allow users to request certificates from a Web interface. You install the Active Directory Certificate Services (AD CS) server role.
What should you do next?
A. Configure the Online Responder Role Service on a member server.
B. Configure the Certificate Enrollment Web Service role service on a domain controller.
C. Configure the Online Responder Role Service on a domain controller.
D. Configure the Certificate Enrollment Web Service role service on a member server.
Answer: D
Explanation:
http://technet.microsoft.com/en-us/library/dd759209.aspx Certificate Enrollment Web Service Overview The Certificate Enrollment Web Service is an Active Directory Certificate Services (AD CS) role service that enables users and computers to perform certificate enrollment by using the HTTPS protocol. Together with the Certificate Enrollment Policy Web Service, this enables policy-based certificate enrollment when the client computer is not a member of a domain or when a domain member is not connected to the domain. Personal note: Since domain controllers are off-limits (regarding open ports), you are left to install the Certificate Enrollment Web Service role service on a plain member server

NEW QUESTION: 3
Assume the following information about a publicly traded automobile manufacturer:
Revenue: $16,000,000
Cash flow: $1,700,000
Net worth per share: $14.55
Current stock price: $30.25 per share
Number of common shares outstanding: 1,300,000
Using this information, what are the price-to-sales, price-to-book, and price-to-cash flow ratios, respectively?
A. The answer cannot entirely be calculated from the information provided.
B. 2.46, 2.08, 23.13
C. 2.46, 0.48, 23.21
D. 1.18, 2.08, 23.13
E. 1.18, 2.08, 23.13
F. None of these answers is correct.
Answer: B
Explanation:
Explanation/Reference:
Explanation:
To calculate the price-to-sales ratio, divide the market price of a common stock by its sales-per share figure. The equation for the price-to-sales ratio is as follows:
Price-to-sales ratio = [P0 / sales per share].
Incorporating the given information into this equation will yield the following:
Price-to-sales ratio = [$30.25 / ($16,000,000 / 1,300,000)] = 2.4578
The calculation of the price-to-book ratio involves dividing the market price of a common stock by its net worth per share. The equation for the price-to-book ratio is as follows:
Price-to-book ratio = [P0 / net worth per share].
Where: net worth per share = (total assets - total liabilities) / # of common shares outstanding.
In this example, the net worth figure has been converted to a per-share basis, and the calculation of the price-to-book ratio is straightforward:
Price-to-book ratio = ($30.35 / $14.55) = 2.0859
The calculation of the price-to-cash flow ratio involves dividing the market price of a common stock by the cash-flow-per-share figure. The calculation of the price-to-cash flow ratio is as follows:
Price-to-cash flow = (P0 / cash flow per share)
Incorporating the given information into this equation will yield the following:
Price-to-cash flow = [$30.35 / (1,700,000 / 1,300,000)] = 23.132

NEW QUESTION: 4
For a request, which object is used for a Java execution of a Rule session?
A. IIrSessionRequest
B. IIrRequest
C. rule Request
D. restAPIRequest
Answer: B


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