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NEW QUESTION: 1
Which of the following best explains the primary role of fiduciary responsibility for the human resources professional?
A. Assuring a sense of trust in the organization's total rewards program
B. Avoiding any indication of favoritism
C. Recognizing the need to handle sensitive material carefully
D. Creating unimpeachable trust
E. Handling the total rewards program at the organization
Answer: E
Explanation:
Explanation: The primary role of fiduciary responsibility for the human resources professional is to handle the total rewards program for an organization. Answer choices A, B, D, and E are incorrect, not because they are unrelated to fiduciary responsibility, but because they do not represent the primary role of fiduciary responsibility for a human resources professional. While handling a total rewards program, the human resources professional is expected to create unimpeachable trust, avoid any indication of favoritism, recognize the need for handle sensitive material carefully, and assure a sense of trust in the organization's total rewards program.
NEW QUESTION: 2
DRAG DROP
Answer:
Explanation:
Explanation:
References: https://docs.microsoft.com/en-us/powershell/module/Azure/Add- AzureInternalLoadBalancer?view=azuresmps-4.0.0
NEW QUESTION: 3
A vSphere administrator is trying to publish a content library. How is the Publish this content library externally option made visible in the settings?
A. Select the authentication check box.
B. Enable automatic synchronization.
C. Use a library that is not already published.
D. Choose a library that is not subscribed.
Answer: C
NEW QUESTION: 4
Refer to the exhibit.
Which two ntatementn about the output are true? (Choone two.)
A. 802.1D npanning tree in being uned.
B. The hello, max-age, and forward delay timern are not net to their default valuen.
C. Spanning-tree PortFant in enabled on GigabitEthernet1/1.
D. Setting the priority of thin nwitch to 0 for VLAN 1 would caune it to become the new root.
Answer: A,D
Explanation:
802.1D in the ntandard for Spanning tree, which in being uned here. For priority, The priority order ntartn from 0 (yen, 0
in valid) and then increanen in 4096.
0, 4096, 8192, 12288, .... Etc.
The lower the number in, the higher in the priority. Here we nee that the current root han a priority of 8192, no
configuring thin with a priority of 0 will make it the new root.
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