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NEW QUESTION: 1
What can cause a Bill Segment to have multiple Bill Calculation Headers?
A. Multiple Contrasts being covered by a Bill Segment
B. Multiple Billable Charges associated to one Contract
C. Multiple Rate Versions
D. Proration at Bill Factor level
E. Proration at Rate Component Level
Answer: C
NEW QUESTION: 2
To allow or prevent load balancing to network 172.16.3.0/24, which of the following commands could be used in R2? (Choose two.)
A. R2(config-if)#bandwidth
B. R2(config-if)#ip ospf priority
C. R2(config-if)#clock rate
D. R2(config-if)#ip ospf cost
E. R2(config-router)#distance ospf
Answer: A,D
Explanation:
Explanation/Reference:
Explanation:
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.shtml#t6 The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher bandwidth indicates a lower cost. There is more overhead (higher cost) and time delays involved in crossing a 56k serial line than crossing a 10M Ethernet line. The formula used to calculate the cost is:
Cost = 10000 0000/bandwidth in bps
For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to cross a T1 line.
By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an interface with the ip ospf cost <value> interface subconfiguration mode command.
NEW QUESTION: 3
조직에서 BYOD (Bring-Your-Own-Device) 작업 환경을 도입했습니다. 다음 중 이 환경에서 발생하는 조직의 네트워크에 대한 위험 증가를 가장 잘 해결하는 정책은 무엇입니까?
A. 조직 데이터에 대한 노출 위험을 줄이기 위해 개인 용도로 직원 장치 사용을 제한합니다.
B. 네트워크 연결 및 데이터 저장에 사용되는 모든 장치에 대한 감지 및 인증 제어를 실시합니다.
C. 장치가 네트워크에 연결될 때 관리 소프트웨어를 사용하여 스캔 한 다음 패치 알림 메시지를 표시합니다.
D. 승인 및 검토 프로세스를 통해 주요 애플리케이션에 대한 관련 액세스를 엄격하게 제어합니다.
Answer: C
NEW QUESTION: 4
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer
A" Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer
A" Country="Australia" />
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
B. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
G. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
Answer: F
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/bb510464.aspx
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