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NEW QUESTION: 1
Give the code fragment:

And the code fragment:

The sendConfirmation() and reserve() methods should be executed in the same transactional context.
Which transaction attributes do you ensure this?
A. No additional annotations are required.
B. Add annotations:@TransactionAttribute (TransactionAttributeType.REQUIRES_NEW) at line
2,@Transactional at line 9 and@TransactionAttribute ((TransactionAttributeType.MANDATORY) at line 12
C. Add annotations:@TransactionAttribute (TransactionAttributeType.REQUIRED) at line
2,@Transactional at line 9 and@TransactionAttribute ((TransactionAttributeType.REQUIRES_NEW) at line 12
D. Add annotations:@TransactionAttribute (TransactionAttributeType.MANDATORY) at line
2,@Transactional at line 9 and@TransactionAttribute ((TransactionAttributeType.REQUIRES_NEW) at line 12
Answer: D

NEW QUESTION: 2
The following is a network diagram for a project.

The total float for the project is how many days?
A. 0
B. 1
C. 2
D. 3
Answer: C

NEW QUESTION: 3
At what layer of the OSI model do routers function on?
A. 0
B. 1
C. 2
D. 3
Answer: B
Explanation:
1 - Physical 2 - Data Link 3 - Network 4 - Transport 5 - Session 6 - Presentation 7 - Application

NEW QUESTION: 4
You have enabled the Slow Query Log for a short period.
When you process the Slow Query Log, you receive the following snip of output:
Count: 100 Time=0 .22a (22s) Lock=0.00s (0s) Rows=0.0 (0), root[root] @localhost
CREATE TABLE 't1' (id serial,id0 varchar(N) unique key,intcaoll INT (N)
,intco12 INT(N) ,intco13 INT(N) ,intco14 INT(N) ,intco15 INT(N)
,charcol1 VARVHAR(N) ,charcol2 VARCHAR(N) charcol3 VARCHAR (N)
,charcol4 VARVHAR(N) ,charcol5 VARCHAR(N) charcol6 VARCHAR (N)
,charcol7 VARVHAR(N) ,charcol8 VARCHAR(N) charcol9 VARCHAR (N) .charcol 10 VACHAR
(N) )
Count: 64000 Time-0.02s (1213s) Lock=0.00s (6s) Rows=1.0 (64000), root [root]@ localhost
SELECT intocl1, intco12, intco13, intco14, intco15, intco16,intco17, intco18
,intcol9, intcol10, charcol1, charcol2, charcol3, charcol4, charcol5, charcol6
,charcol7, charcol8, charcol9, charcol10 FROM t1 WHERE id = 's'
Count: 1 Time=0.02s (0s) Lock=0.00s (0s) Rows=1.0 (1) agent [agent] @localhost
SELECT Select_priv, Repl_client_priv, Show_db_priv, Super_priv,
Process_priv FROM mysql.user WHERE CONCAT (user, 's', host) = CURRENT_USER ()
Count: 48000 Time=0.02s (778s) Lock=0.00 (3s) Rows=1.0 (48000), root[root]@localhost
SELECT intocl1,intcol2,intcol3, intcol4, intcol5, charcol1, charcol2, charcol3
,charcol4, charcol5, charcol6, charcol7, charcol8, charcol9, charcol10 FROM t1 WHERE id = 's'
You want to tune the query such that it provides the greatest overall time savings.
Which query will accomplish this?
A. SELECT intcol1, intcol2, intcol3, intcol4, intcol5, charcol1, charcol2, charcol3, charcol4,
charcol5, charcol6, charcol7, charcol8, charcol9, charcol10
FROM t1
WHERE id = 's';
B. CHEATE TABLE 't1' (id serial, id0 varchar (N) unique key, intcol1 INT (N)
,intcol2 INT (N), intcol3 INT(N) ,intcol4 INT(N), intcol5 INT(N), charool1 VARCHAR
(N)
,charcol2 VARCHAR (N), charcol3 VARCHAR(N), charcol4 VARCHAR(N), charcol5 VARCHAR
(N)
,charcol6 VARCHAR (N), charcol7 VARCHAR(N), charcol8 VARCHAR(N), charcol9 VARCHAR
(N)
,charcol10 VARCHAR (N);
C. SELECT intcol1, intcol2, intcol3, intcol4, intcol5, intcol6, intcol7, intcol8, intcol9,
Intcol10, intcol11, intcol12, intcol13, intcol14, intcol15, intcol16, intcol17, intcol18, intcol19,
charcol10
FROM t1
WHERE id = 's';
D. SELECT Select_priv, Repl_client_priv, Show_db_priv, Super_priv, Process_priv
FROM mysql.user
WHERE CONCAT (user,'s', host) = CURRENT_USER();
Answer: B