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NEW QUESTION: 1
A. thead:only-child, tbody:after, table:before
B. tr:first-line, tr:last-child
C. tr:first-of-type, tr:last-of-type
D. tr [line |-0, 1, 3]
Answer: C
Explanation:
tr.first-of-type
The :first-of-type selector matches every element that is the first child, of a particular type,
of its parent.
Here the first line of table.
tr.last-of-type
The :last-of-type pseudo-class represents an element that is the last sibling of its type in
the list of children of its parent element.
NEW QUESTION: 2
Spanning Tree Protocol calculates path cost based on which of these?
A. bridge priority
B. interface bandwidth and delay
C. interface bandwidth
D. interface delay
E. hop count
Answer: C
Explanation:
STP calculates the path cost based on the media speed (bandwidth) of the links between switches and the port cost of each port forwarding frame. Spanning tree selects the root port based on the
path cost. The port with the lowest path cost to the root bridge becomes the root port. The root
port is always in the forwarding state.
If the speed/duplex of the port is changed, spanning tree recalculates the path cost automatically.
A change in the path cost can change the spanning tree topology.
Data rate and STP path cost
The table below shows the default cost of an interface for a given data rate.
NEW QUESTION: 3
Refer to the exhibit.
If uplink 1 fails, to which addresses will Fabric Interconnect B transmit a GARP on Uplink 2?
A. A1, B1, AA, and BB
B. C1 and C2 only
C. AA and BB only
D. No GARPs will be transmitted
E. AA, BB, C1, and C2
Answer: E
NEW QUESTION: 4
Which two statements about IPv6 multicast addresses are true? (Choose two.)
A. They identify a group of interfaces on different devices
B. They use the prefix FC80::/8
C. If the lifetime parameter is set to 1, the route is permanent
D. If the scope parameter is set to 5, the route is local to the node
E. They use the prefix FF00::/8
Answer: A,E
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