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NEW QUESTION: 1
In your schema, the DEPARTMENTS table contains the columns DEPARTMENT_ID and DEPARTMENT_NAME.
You want to display the department name for existing department id 10.
With SERVEROUTPUT enabled, which two blocks of code will give the required output?
A. DECLAREcv1 SYS_REFCURSOR;v_dept_name
departments.department_name%TYPE;BEGINEXECUTE IMMEDIATE 'BEGIN OPEN: cv1 FORSELECT department_name FROM departmnets WHERE department_id=10: END;'USING IN cv1;FETCH cv1 INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);CLOSE cv1;END;
B. DECLARETYPE dept_cur IS REF CURSOR RETURN departments%ROWTYPE;cv1
dept_cur;v_dept_name departments.department_name%TYPE;BEGINOPEN cv1 FOR SELECT * FROM departments WHERE department_id=10;FETCH cv1. department_name INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);CLOSE cv1;END;
C. DECLARETYPE names_t IS TABLE OF SYS_REFCURSOR INDEX BY PLS_INTEGER;cv1 names_t;v_dept_name departments.department_name%TYPE;BEGINOPEN cv1 FOR SELECT department_name FROM departments WHERE department_id=10;FETCH cv1 INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);CLOSE cv1;END;
D. DECLARETYPE dept_cur IS REF CURSOR;cv1 dept_cur;v_dept_name departments.
department_name%TYPE;BEGINOPEN cv1 FOR SELECT department_name FROM departments WHERE department_id=10;IF cv1 IS NOT NULL THENFETCH cv1 INTO v_dept_name;DBMS_OUTPUT.PUT_LINE (v_dept_name);END IFCLOSE cv1;END;
Answer: A,D
NEW QUESTION: 2
What value can you select when you execute the Reset Process Instance program?
A. user Id
B. Copy Mode
C. Date and time
D. Process Instance ID
Answer: D
NEW QUESTION: 3
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
C. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
D. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
E. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
F. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
G. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
H. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
Answer: B
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
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