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NEW QUESTION: 1
What can cause a Bill Segment to have multiple Bill Calculation Headers?
A. Proration at Rate Component Level
B. Multiple Rate Versions
C. Multiple Billable Charges associated to one Contract
D. Proration at Bill Factor level
E. Multiple Contrasts being covered by a Bill Segment
Answer: B
NEW QUESTION: 2
To allow or prevent load balancing to network 172.16.3.0/24, which of the following commands could be used in R2? (Choose two.)
A. R2(config-if)#bandwidth
B. R2(config-router)#distance ospf
C. R2(config-if)#ip ospf cost
D. R2(config-if)#ip ospf priority
E. R2(config-if)#clock rate
Answer: A,C
Explanation:
Explanation/Reference:
Explanation:
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.shtml#t6 The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher bandwidth indicates a lower cost. There is more overhead (higher cost) and time delays involved in crossing a 56k serial line than crossing a 10M Ethernet line. The formula used to calculate the cost is:
Cost = 10000 0000/bandwidth in bps
For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to cross a T1 line.
By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an interface with the ip ospf cost <value> interface subconfiguration mode command.
NEW QUESTION: 3
조직에서 BYOD (Bring-Your-Own-Device) 작업 환경을 도입했습니다. 다음 중 이 환경에서 발생하는 조직의 네트워크에 대한 위험 증가를 가장 잘 해결하는 정책은 무엇입니까?
A. 장치가 네트워크에 연결될 때 관리 소프트웨어를 사용하여 스캔 한 다음 패치 알림 메시지를 표시합니다.
B. 네트워크 연결 및 데이터 저장에 사용되는 모든 장치에 대한 감지 및 인증 제어를 실시합니다.
C. 승인 및 검토 프로세스를 통해 주요 애플리케이션에 대한 관련 액세스를 엄격하게 제어합니다.
D. 조직 데이터에 대한 노출 위험을 줄이기 위해 개인 용도로 직원 장치 사용을 제한합니다.
Answer: A
NEW QUESTION: 4
<row OrderId="1" OrderDate="2000-01-01T00:00:00" Amount="3400.00" Name="Customer
A" Country="Australia" />
<row OrderId="2" OrderDate="2001-01-01T00:00:00" Amount="4300.00" Name="Customer
A" Country="Australia" />
Which Transact-SQL query should you use?
A. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
B. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
C. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW, ELEMENTS
D. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
E. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
H. SELECT Name, Country, OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
Answer: F
Explanation:
Reference: http://msdn.microsoft.com/en-us/library/bb510464.aspx
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