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NEW QUESTION: 1
A user has changed the MAC address of a laptop to gain access to a network. This is an instance of:
A. a botnet
B. brute force
C. spoofing
D. man-in-the-middle
Answer: C

NEW QUESTION: 2
A security administrator discovered that all communication over the company's encrypted wireless network
is being captured by savvy employees with a wireless sniffing tool and is then being decrypted in an
attempt to steal other employee's credentials. Which of the following technology is MOST likely in use on
the company's wireless?
A. WPA with TKIP
B. WEP128-PSK
C. VPN over open wireless
D. WPA2-Enterprise
Answer: B
Explanation:
Section: Threats and Vulnerabilities
Explanation/Reference:
Explanation:
WEP's major weakness is its use of static encryption keys. When you set up a router with a WEP
encryption key, that one key is used by every device on your network to encrypt every packet that's
transmitted. But the fact that packets are encrypted doesn't prevent them from being intercepted, and due
to some esoteric technical flaws it's entirely possible for an eavesdropper to intercept enough WEP-
encrypted packets to eventually deduce what the key is.
This problem used to be something you could mitigate by periodically changing the WEP key (which is why
routers generally allow you to store up to four keys). But few bothers to do this because changing WEP
keys is inconvenient and time-consuming because it has to be done not just on the router, but on every
device that connects to it. As a result, most people just set up a single key and then continue using it ad
infinitum.
Even worse, for those that do change the WEP key, new research and developments reinforce how even
changing WEP keys frequently is no longer sufficient to protect a WLAN. The process of 'cracking' a WEP
key used to require that a malicious hacker intercept millions of packets plus spend a fair amount of time
and computing power. Researchers in the computer science department of a German university recently
demonstrated the capability to compromise a WEP-protected network very quickly. After spending less
than a minute intercepting data (fewer than 100,000 packets in all) they were able to compromise a WEP
key in just three seconds.

NEW QUESTION: 3
人気のある製品のWebトラフィックを処理するために、最高財務責任者とITディレクタは、10 m1の大利用率のリザーブドインスタンス（RI）を購入しました。ルート53はElastic Load Balancer（ELB）にトラフィックを配信するために使用されます。数ヵ月後、製品はさらに人気が高まり、追加の容量が必要になります。その結果、あなたの会社は2つのc3.2倍の中程度の使用率のRIを購入します。
2つのc3.2xlargeインスタンスをELBに登録すると、m1.largeインスタンスの容量が100％で、c3.2xlargeインスタンスの未使用容量がかなり大きいことがすぐにわかります。どのオプションが最も費用対効果が高く、EC2容量を最も効果的に使用しますか？
A. Cloudwatchによってトリガーされたときに最大10個のオンデマンドm1.largeインスタンスを追加するように、[Auto Scaling]グループと[Launch Configuration]を[ELB]で設定します。 c3.2xlargeインスタンスを停止します。
B. インスタンスタイプごとに個別のELBを使用し、Route 53加重ラウンドロビン方式でELBに負荷を分散します。
C. Route 53レイテンシベースのルーティングとヘルスチェックを使用して、トラフィックをEC2 m1.largeおよびc3.2xlargeインスタンスに直接ルーティングします。 ELBを遮断します。
D. 2つのc3.2xlargeインスタンスでELBを構成し、最大2つの追加のc3.2xlargeインスタンスにオンデマンドの自動スケーリンググループを使用します。 m1.largeインスタンスを停止します。
Answer: B

NEW QUESTION: 4
Consider these three statements:
create view v1 as select department_id,department_name,last_name from departments join employees using (department_id); select department_name,last_name from v1 where department_id=20; select d.department_name,e.last_name from departments d, employees ewhere d.department_id=e.department_id and d.department_id=20; The first query will be quicker than the second because:
A. The view is precompiled, so the first query requires less dynamic compilation than the second query.
B. There is no reason for the first query to be quicker.
C. The view has already done the work of joining the tables.
D. The view uses ISO standard join syntax, which is faster than the Oracle join syntax used in the second query.
Answer: B