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NEW QUESTION: 1
The GHF Corporation is looking to hire four software developers. The average pay for software developers, with the desired skill set, is $76,000. The GHF Corporation believes that by offering $80,000 for the starting salary they'll attract better performers than their competitors. What is this scenario an example of?
A. Matching the market
B. Leading the market
C. Lagging the market
D. Beating the market
Answer: B
NEW QUESTION: 2
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution. Determine whether the solution meets the stated goals.
Your network contains an Active Directory domain named contoso.com. The domain contains a DNS server named Server1. All client computers run Windows 10.
On Server1, you have the following zone configuration.
You need to ensure that all of the client computers in the domain perform DNSSEC validation for the fabrikam.com namespace.
Solution: From a Group Policy object (GPO) in the domain, you modify the Network List Manager Policies.
Does this meet the goal?
A. Yes
B. No
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Network List Manager Policies are security settings that you can use to configure different aspects of how networks are listed and displayed on one computer or on many computers.
Network List Manager Policies are not related to DNSSEC.
References: https://technet.microsoft.com/en-us/library/jj966256(v=ws.11).aspx
NEW QUESTION: 3
重要なデータベース・スケジューラー・ジョブの経過時間が許容できないほど長くなっていることがわかります。
ジョブはスケジューラー・ジョブ・クラスに属し、スケジューラー・ウィンドウで実行されます。
どの2つのアクションがジョブの経過時間を短縮することができますか？ （2つを選択してください）
A. 所属するジョブ・クラス内のジョブの相対優先順位を上げる
B. ジョブが属するスケジューラウィンドウの優先度を上げる
C. スケジューラ・ウィンドウに関連付けられたリソース・マネージャ・プラン内のジョブ・クラスにマップされたコンシューマ・グループのリソース割当ての増加
D. JOB_QUEUE_PROCESSESパラメータの値を増やす
E. スケジュールと期間が同じ既存のより高い優先度のスケジューラウィンドウにジョブを移動する
Answer: A,C
NEW QUESTION: 4
Examine the description of the CUSTOMERS table:
The CUSTOMER_ID column is the primary key for the table.
Which statement returns the city address and the number of customers in the cities Los Angeles or San Francisco?
A. SELECT city_address, COUNT (*)
FROMcustomers
WHERE city address IN ( 'Los Angeles', 'San Fransisco')
GROUP BY city_address;
B. SELECT city_address, COUNT(customer_id)
FROMcustomers
WHERE city_address IN ( 'Los Angeles', 'San Fransisco')
GROUP BYcity_address, customer_id;
C. SELECT city_address, COUNT(*)
FROM customers
WHERE city_address IN ( 'Los Angeles', 'San Fransisco');
D. SELECT city_address, COUNT (customer_id)
FROM customers
GROUP BY city_address IN ( 'Los Angeles', 'San Fransisco');
Answer: A
Explanation:
Not C: The customer ID in the GROUP BY clause is wrong
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