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NEW QUESTION: 1
View the exhibit, which contains the partial output of an IKE real-time debug, and then answer the question below.
ike 0: comes 10.0.0.2:500->10.0.0.1:500, ifindex=7....
ike 0: IKEv1 exchange=Aggressive id=baf47d0988e9237f/2f405ef3952f6fda len=430
ike 0: in BAF47D0988E9237F2F405EF3952F6FDA0110040000000000000001AE0400003C0000000100000001000000300101000
ike 0:RemoteSite:4: initiator: aggressive mode get 1st response...
ike 0:RemoteSite:4: VID RFC 3947 4A131c81070358455C5728F20E95452F
ike 0:RemoteSite:4: VID DPD AFCAD71368A1F1C96B8696FC77570100
ike 0:RemoteSite:4: VID FORTIGATE 8299031757A36082C6A621DE000502D7
ike 0:RemoteSite:4: peer is FortiGate/Fortios (v5 b727)
ike 0:RemoteSite:4: VID FRAGMENTATION 4048B7D56EBCE88525E7DE7F00D6C2D3
ike 0:RemoteSite:4: VID FRAGMENTATION 4048B7D56EBCE88525E7DE7F00D6C2D3C0000000
ike 0:RemoteSite:4: received peer identifier FQDN 'remore'
ike 0:RemoteSite:4: negotiation result
ike 0:RemoteSite:4: proposal id = 1:
ike 0:RemoteSite:4: protocol id = ISAKMP:
ike 0:RemoteSite:4: trans_id = KEY_IKE.
ike 0:RemoteSite:4: encapsulation = IKE/none
ike 0:RemoteSite:4: type=OAKLEY_ENCRYPT_ALG, val=AES_CBC, key -len=128
ike 0:RemoteSite:4: type=OAKLEY_HASH_ALG, val=SHA.
ike 0:RemoteSite:4: type-AUTH_METHOD, val=PRESHARED_KEY.
ike 0:RemoteSite:4: type=OAKLEY_GROUP, val=MODP1024.
ike 0:RemoteSite:4: ISAKMP SA lifetime=86400
ike 0:RemoteSite:4: ISAKMP SA baf47d0988e9237f/2f405ef3952f6fda key 16: B25B6C9384D8BDB24E3DA3DC90CF5E73
ike 0:RemoteSite:4: PSK authentication succeeded
ike 0:RemoteSite:4: authentication OK
ike 0:RemoteSite:4: add INITIAL-CONTACT
ike 0:RemoteSite:4: enc BAF47D0988E9237F405EF3952F6FDA081004010000000000000080140000181F2E48BFD8E9D603F
ike 0:RemoteSite:4: out BAF47D0988E9237F405EF3952F6FDA08100401000000000000008C2E3FC9BA061816A396F009A12
ike 0:RemoteSite:4: sent IKE msg (agg_i2send): 10.0.0.1:500-10.0.0.2:500, len=140, id=baf47d0988e9237f/2
ike 0:RemoteSite:4: established IKE SA baf47d0988e9237f/2f405ef3952f6fda
Which statements about this debug output are correct? (Choose two.)
A. The initiator has provided remote as its IPsec peer ID.
B. It shows a phase 1 negotiation.
C. The negotiation is using AES128 encryption with CBC hash.
D. The remote gateway IP address is 10.0.0.1.
Answer: A,B
NEW QUESTION: 2
View Exhibit1 and examine the structure of the product table.
View Exhiblt2 and examine the procedure you created. The procedure uses the prod id to determine whether the list price is within a given range.
You then create the following trigger on the product table.
CREATE OR REPLACE TRIGGER check_price__trg
BEF0RE INSERT OR UPDATE OF prod_id, prod_list_price
ON product FOR EACH ROW
WHEN (nev.prod_id <> NVX(old.prod_id,0) OR
New.prod__list_price <> NVL(old.prod_list_price, 0) )
BEGIN
check_price (:new.prod_id) ;
END
/
Examine the following update command for an existing row in the product table.
SQL> UPDATE produce SET prod_list_price = 10 WHERE prod_id=115;
Why does it generate an error?
A. because the condition specified in the when clause is not valid
B. because the procedure call in the trigger is not valid "
C. because the column list specified with UPDATE in the trigger is not valid
D. because both the procedure and trigger access the same table
E. because the WHEN clause cannot be used with a row-level trigger
Answer: D
NEW QUESTION: 3
A. IF(Discontinued = 0, 'Active', 'Inactive')
B. CASE Discontinued
WHEN 0 THEN 'Active'
WHEN 1 THEN 'Inactive'
END
C. IF Discontinued = 0
'Active'
ELSE
'Inactive'
D. DECODE (Discontinued, 0, 'Active', 1, 'Inactive', 'Unknown')
Answer: B
Explanation:
Explanation
The CASE statement evaluates a list of conditions and returns one of multiple possible result expressions.
The CASE expression has two formats:
The simple CASE expression compares an expression to a set of simple expressions to determine the result.
The searched CASE expression evaluates a set of Boolean expressions to determine the result.
Both formats support an optional ELSE argument.
CASE can be used in any statement or clause that allows a valid expression.
References:
https://docs.microsoft.com/en-us/sql/t-sql/language-elements/case-transact-sql?view=sql-server-2017
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