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NEW QUESTION: 1
How can a Citrix Engineer update applications in an AppLayering environment?
A. Install applications with automatic updates into the OS layer.
B. Grant the user administrative rights to update the applications.
C. Enable automatic updates in the App Layers.
D. Create a new application layer and install the updated version of the application in it.
Answer: D
NEW QUESTION: 2
You have established an MSDP peering between multicast domains for your AS and a neighboring AS. You are concerned about unnecessary flooding or looping of source active messages between MSDP peers. Which MSDP mechanism is used to prevent this problem?
A. The receiving MSDP peer sends register-stop messages towards the originating RP that forwarded the SA messages.
B. The receiving MSDP peer performs a multicast RPF check to ensure that the SA messages are forwarded away from only the originating multicast source.
C. The receiving MSDP peer performs amulticast peer-RPF check to ensure that the SA messages are forwarded away from only the originating RP.
D. The receiving MSDP peer sends prune messages to all upstream neighbors to avoid receiving additional SA messages.
Answer: C
NEW QUESTION: 3
Siehe Ausstellung. Welche Adress- und Maskenkombination stellt eine Zusammenfassung der von EIGRP gelernten Routen dar?
A. 192.168.25.28 255.255.255.252
B. 192.168.25.0 255.255.255.240
C. 192.168.25.0 255.255.255.252
D. 192.168.25.16 255.255.255.240
E. 192.168.25.28 255.255.255.240
F. 192.168.25.16 255.255.255.252
Answer: D
Explanation:
The binary version of 20 is 10100.
The binary version of 16 is 10000.
The binary version of 24 is 11000.
The binary version of 28 is 11100.
The subnet mask is /28. The mask is 255.255.255.240.
Note:
From the output above, EIGRP learned 4 routes and we need to find out the summary of them:
+ 192.168.25.16
+ 192.168.25.20
+ 192.168.25.24
+ 192.168.25.28
-> The increment should bE. 28 ?16 = 12 but 12 is not an exponentiation of 2 so we must choose 16 (24). Therefore the subnet mask is /28 (=1111 1111.1111 1111.1111 1111.11110000) = 255.255.255.240 So the best answer should be 192.168.25.16 255.255.255.240
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