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You need to decide which one to focus on.
NEW QUESTION: 1
You administer a Microsoft SQL Server 2012 database named ContosoDb. Tables are defined as shown in the exhibit. (Click the Exhibit button.)
You need to display rows from the Orders table for the Customers row having the CustomerId value set to 1 in the following XML format.
Which Transact-SQL query should you use?
A. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
B. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
C. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers=CustomerId = 1 FOR XML RAW, ELEMENTS
D. SELECT Name AS '@Name', Country AS '@Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
E. SELECT Name, Country, OrderId, OrderDate, Amount
FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML AUTO, ELEMENTS
G. SELECT Name AS 'Customers/Name', Country AS 'Customers/Country', OrderId, OrderDate, Amount FROM Orders INNER JOIN Customers ON Orders.CustomerId= Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers')
H. SELECT OrderId, OrderDate, Amount, Name, Country
FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML RAW
Answer: A
Explanation:
Reference:
http://msdn.microsoft.com/en-us/library/ms188273.aspx
NEW QUESTION: 2
End Item A can be substituted with End Item B and End Item B can be substituted with End Item
C. The effective dates for these substitutions are given in the Exhibit.
Which three statements are correct?
A. The inferred substitution rule between Item A and C is effective from 06-JAN-2008 to 22-JAN- 2008.
B. End Item A substitution with End Item C Is Inferred.
C. If End Item A Is requested, it can be satisfied with the supplies from End Items A or B or C.
D. The inferred substitution rule between Item A and C is effective only from 06-JAN-2008 to 10- JAN-2008.
E. End Item A substitution with End Item C is not possible.
Answer: A,B,D
NEW QUESTION: 3
What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} }; ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
B t2[]={5,6,8,2,1};
vector<B> v1(10,0);
sort(t1, t1+5);
sort(t2, t2+5);
set_symmetric_difference(t2,t2+5,t1,t1+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
A. 3 4 6 8 0 0 0 0 0 0
B. 6 8 3 4 0 0 0 0 0 0
C. 3 4 0 0 0 0 0 0 0 0
D. 6 8 0 0 0 0 0 0 0 0
E. compilation error
Answer: A
NEW QUESTION: 4
Given:
12.import java.util.*;
13.public class Explorer3 {
14.public static void main(String[] args) {
15.TreeSet<Integer> s = new TreeSet<Integer>();
16.TreeSet<Integer> subs = new TreeSet<Integer>();
17.for(int i = 606; i < 613; i++)
18.if(i%2 == 0) s.add(i);
19.subs = (TreeSet)s.subSet(608, true, 611, true);
20.subs.add(629);
21.System.out.println(s + " " + subs);
22.}
23.}
What is the result?
A. Compilation fails.
B. [606, 608, 610, 612, 629] [608, 610]
C. An exception is thrown at runtime.
D. [608, 610, 612, 629] [608, 610]
E. [606, 608, 610, 612, 629] [608, 610, 629]
F. [608, 610, 612, 629] [608, 610, 629]
Answer: E
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